[LeetCode] Arrays 101: Find Numbers with Even Number of Digits

문제

숫자 배열이 주어지면, 짝수 자리인 수의 개수를 반환해라

Given an array nums of integers, return how many of them contain an even number of digits.

 

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.

 

Constraints:

• 1 <= nums.length <= 500
• 1 <= nums[i] <= 105

 

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Code

var findNumbers = function(nums) {
    let ans = 0;
    for(let i = 0; i< nums.length; i++) {
        if(nums[i].toString().length % 2 === 0) ans++;
    }
    
    return ans;
};