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[LeetCode] Arrays 101: Remove Element 본문

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[LeetCode] Arrays 101: Remove Element

따봉도치 2022. 4. 7. 18:10

문제

정수 배열 nums와 정수 val을 제공받아, nums에서 모든 val 값을 제거하세요.

배열의 사이즈를 변경하지 못하는 언어일 경우, 배열의 첫 요소부터 결과를 저장하고 결과 값의 개수 k를 반환하세요.

다른 배열에 추가 메모리를 할당하지 말고 해결하세요.

 

Given an integer array nums and an integer val, remove all occurrences of val in nums in-place. The relative order of the elements may be changed.

Since it is impossible to change the length of the array in some languages, you must instead have the result be placed in the first part of the array nums. More formally, if there are k elements after removing the duplicates, then the first k elements of nums should hold the final result. It does not matter what you leave beyond the first k elements.

Return k after placing the final result in the first k slots of nums.

Do not allocate extra space for another array. You must do this by modifying the input array in-place with O(1) extra memory.

 

Custom Judge:

The judge will test your solution with the following code:

int[] nums = [...]; // Input array
int val = ...; // Value to remove
int[] expectedNums = [...]; // The expected answer with correct length.
                            // It is sorted with no values equaling val.

int k = removeElement(nums, val); // Calls your implementation

assert k == expectedNums.length;
sort(nums, 0, k); // Sort the first k elements of nums
for (int i = 0; i < actualLength; i++) {
    assert nums[i] == expectedNums[i];
}

If all assertions pass, then your solution will be accepted.

 

Example 1:

Input: nums = [3,2,2,3], val = 3
Output: 2, nums = [2,2,_,_]
Explanation: Your function should return k = 2, with the first two elements of nums being 2.
It does not matter what you leave beyond the returned k (hence they are underscores).

Example 2:

Input: nums = [0,1,2,2,3,0,4,2], val = 2
Output: 5, nums = [0,1,4,0,3,_,_,_]
Explanation: Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4.
Note that the five elements can be returned in any order.
It does not matter what you leave beyond the returned k (hence they are underscores).

 

Constraints:

  • 0 <= nums.length <= 100
  • 0 <= nums[i] <= 50
  • 0 <= val <= 100

 


Code

1) splice를 통해 삭제

var removeElement = function(nums, val) {
	// 0 부터 돌게 되면, 배열 길이 달라져서 indexing 문제 생김
    for (let i = nums.length - 1; i >= 0; i--) {
        if (nums[i] == val) {
            nums.splice(i, 1);
        }
    }
};

 

2) 삭제하지 않고 해결

var removeElement = function(nums, val) {
     let idx = 0;
     for (let i in nums) {
         if (nums[i] !== val) {
             nums[idx++] = nums[i];
         }
     }
    
     return idx;
};
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